Most crash games let you place 2 or more bets per round — but how should you split them? A $5 safe bet at 1.5× plus a $5 moon shot at 10× plays very differently from two $5 bets at 3×. This calculator shows the exact combined probability, EV, and outcome breakdown for any multi-bet configuration so you can see what each strategy actually costs.
| Scenario | Probability | Visual | Gross Payout | Net P/L | Freq (1 in N) |
|---|
How This Calculator Works
Each bet in a crash game is independent — they share the same crash point, but your cashout targets determine whether each bet wins or loses individually. With a crash point of 3.5×: a bet targeting 2× wins, while a bet targeting 5× loses. Same round, different outcomes per bet.
Probability per bet: P(win) = (1 / target) × (1 - house_edge). For two bets, since they share the same crash point, the outcomes are not independent. If Bet 1 targets 2× and Bet 2 targets 5×: whenever Bet 2 wins (crash ≥ 5×), Bet 1 also wins. But Bet 1 can win without Bet 2 (crash between 2× and 5×).
Combined EV: The total expected value is simply EV₁ + EV₂ + EV₃. Each bet's EV equals P(win) × profit - P(lose) × bet. Multi-betting doesn't change the house edge — it just changes how you distribute your stake across different risk targets.
Key insight: Dual betting doesn't reduce the house edge. Whether you bet $10 on one target or split $5 + $5 across two targets, the expected loss is identical: total_stake × house_edge. The difference is in variance and hit frequency — a barbell strategy (low target + high target) gives you frequent small wins and occasional big wins, while equal splits give more consistent medium results.
Disclaimer: Multi-betting does not change the mathematical house edge. Expected loss always equals total stake × house edge regardless of how bets are split. These calculations assume standard crash game probability distribution. Only gamble with money you can afford to lose. BeGambleAware.org